Answers
Assignment - 1
Ans 1. (i) 4            (ii) 2

Ans 2.  0.86

Ans 3. 5960 kg m3

Ans 4.  We know  
0F = 9/5(0C) + 32
0F = 9/5(37) + 32
0F = 9 × 7.4 + 32 = 98.6 0F

Ans 5. Let x be the common reading.
Then, C = F = x
We know the relation between 0C and 0F
0C=5/9 (0F-32), and substituting x for 0C and 0F, we get
x =5/9 (x-32)
x =5/9x - 5/9×32
x - 5/9x = 5×32/9
4/9x = - 5×32/9
x = - 5×32/4 = -40
So, -40 0C = -400F
Hence, at -40 degrees , the readings on the Celsius scale and the Fahrenheit scales are the same.

Ans 6. i). 4.8 × 10-4                   ii) 2.34 × 105

Ans 7. 3,3,3

Ans 8. (d) All of these

Ans 9. (b)  Calculate the average value of different titre values.
Then use the rule to determine the significant figures for mathematical calculation.  
                   Average value =  25.2  +  25.25  +  25.0  =   75.45
                                                                  3                            3                
= 25.15  = 25.2 mL  The number of significant figure is 3

Ans 10. (b)  The answer is to be reported up to same number of decimal places as that of the term with the least number of decimal places. This after rounding off 71.02 becomes 71.0.