Answers
Assignment - 1
Ans 1. (i) 4 (ii) 2
Ans 2. 0.86
Ans 3. 5960 kg m3
Ans 4. We know
0F = 9/5(0C) +
32
0F = 9/5(37) + 32
0F
= 9 × 7.4 + 32 = 98.6 0F
Ans 5. Let x be the
common reading.
Then, C = F = x
We know the relation between 0C and 0F
0C=5/9 (0F-32),
and substituting x for 0C and 0F, we get
x =5/9 (x-32)
x =5/9x - 5/9×32
x - 5/9x = 5×32/9
4/9x = - 5×32/9
x = - 5×32/4 = -40
So, -40 0C = -400F
Hence, at -40 degrees , the readings on
the Celsius scale and the Fahrenheit scales are the same.
Ans 6. i). 4.8 × 10-4
ii) 2.34 × 105
Ans 7. 3,3,3
Ans 8. (d) All of these
Ans 9. (b) Calculate the average value of different
titre values.
Then use the rule to determine the
significant figures for mathematical calculation.
Average value = 25.2
+ 25.25 + 25.0 = 75.45
3 3
= 25.15 = 25.2
mL The number of significant figure is 3
Ans 10. (b) The answer is to be reported up to same
number of decimal places as that of the term with the least number of decimal
places. This after rounding off 71.02 becomes 71.0.
0 Comments