Answers
Assignment - 2
Ans
2. We Know
i).
Number of Moles = Given Mass/ Atomic Mass
Given
Mass of Na = 46 g
No
Of moles of 46g of Na = 46/23 = 2 mol
iv).
Number of Moles = Given Mass/ Molecular Mass
Given
Mass of H2SO4 = 49 g
No
Of moles of 46g of Na = 49/98 = 0.5 mol.
Rest Part of Que 2 do Yourself
Ans
3.
We Know
Number
of Moles = Given Mass/ Molecular Mass
Number
of moles of K = 4.7/39 = 0.12 mol
Ans
4.
We Know
Number
of Moles = Given Mass/ Molecular Mass
9.2
× 10-4 = Mass of Argon (Given Mass) / 40
Mass
of Argon (Given Mass) = 9.2 × 10-4 × 40 = 0.037 g
Ans
5.
We Know
Number
of Atoms/Molecules = Number of Moles × Avogadro’s No.
No.
of moles of Cu = 5/63.5 = 0.079 mol
Number
of Atoms = 0.079 × 6.022 × 1023
=
4.74 × 1022 atoms of Cu
Ans
6. We Know
Number
of Atoms/Molecules = Number of Moles × Avogadro’s No.
No
of Moles of Saccharin = 0.040/183.18 = 0.000218 mol
Number
of Molecules = 0.000218 × 6.022 × 1023 = 0.00131 × 1023
=
1.3 × 1020 Molecules
The
compound’s formula (C7H5NO3S) shows that each
molecule contains 7 carbon atoms, so the number of C atoms in the given sample
is: 7 × 1.3 × 1020 = 9.1 × 1020
atoms.
Que 7. How many C4H10 molecules are
contained in 9.213 g of this compound? How many hydrogen atoms?
Que 8. What is the mass of 0.443 mol of
hydrazine, N2H4?
Que 9. How many moles of sucrose, C12H22O11,
are in a 25g sample of sucrose?
Que10. A prospector panning for gold in a
river collects 15.00 g of pure gold. How many Au atoms are in this quantity of
gold?
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