Answers Assertion Reason and Matching types 


Assertion and Reason Type

1. (i)                   2. (ii)               3. (iii)              4. (iii)

         Matching type:

5. (i) → (e)        (ii) → (d)        (iii) → (b)       (iv) → (g)        (v) → (c), (h) (vi) → (f) (vii) → (a) (viii) → (i)

 

Q6. Ratio of no. of atoms in the molecule

9/12 : 1/1 : 3.5/14 = 0.75 : 1 : 0.25 = 3 : 4 :1

Empirical formula = C3H4N;

M.F. = (C3H4N)n

n × Empirical formula mass = Molecular mass

n (3×12+4+14) =108

n × 54= 108

n = 2

M.F. = C6H8N2

 

Q7. geq of HCI = 3/36.5 × 2.5 = 0.20548 = geq of Al(OH)3

Weight of AI(OH)3 = 0.20548 × 78/3

No of tablets = 5342/400 = 13.35 = 14

 

Q8.  BaCO3 → BaO + CO2

192 g of BaCO3 1 gives mole of CO2 = 22.4 L

9.85 g of BaCO3 will give 0.05 mole of CO2 which is equal to 1.12 litre.